16c^2-28c+9=-4c

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Solution for 16c^2-28c+9=-4c equation: 



16c^2-28c+9=-4c

We move all terms to the left:

16c^2-28c+9-(-4c)=0

We get rid of parentheses

16c^2-28c+4c+9=0

We add all the numbers together, and all the variables

16c^2-24c+9=0

a = 16; b = -24; c = +9;
Δ = b2-4ac
Δ = -242-4·16·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{24}{32}=3/4$

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